6x^2+1x-52=0

Solution for 6x^2+1x-52=0 equation:

6x^2+1x-52=0

We add all the numbers together, and all the variables

6x^2+x-52=0

a = 6; b = 1; c = -52;
Δ = b2-4ac
Δ = 12-4·6·(-52)
Δ = 1249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1249}}{2*6}=\frac{-1-\sqrt{1249}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1249}}{2*6}=\frac{-1+\sqrt{1249}}{12}
$